# How do you solve #2* 3^x = 7* 5^x#?

##### 1 Answer

Jul 19, 2015

I found:

#### Explanation:

Try rearranging it: as:

write it as:

use the definition of logarithm to write:

We can now use the change of base formula to transform our log into a quocient of natural logs (these can be evaluated using a pocket calculator) as: